# Coffee Break: No touching allowed

#### lookagain

##### Senior Member
$$\displaystyle C$$
$$\displaystyle F \ \ \ A$$
$$\displaystyle I \ \ \ \ D \ \ \ J$$
$$\displaystyle \ \ \ \ \ \ B \ \ \ H$$
$$\displaystyle G \ \ \ E$$

#### greg1313

##### New member
Yes, if only mmm4444bot had not created another username "Otis," posts/threads like the one above would be under
just the one username all along. lookagain, I see you tried to give him/her "an out" by deleting that post # 16 in that
other thread. And this username, "greg1313," would not exist in response to the creation of "Otis."

But live and learn must mmm4444bot. (With apologies to Yoda.)

Note: Please keep scrolling down to see every step.

For convenience, I let A = 1, ... , J = 10.

We have the equivalent of:

$$\displaystyle *$$
$$\displaystyle 6 \ \ \ *$$
$$\displaystyle * \ \ * \ \ *$$
$$\displaystyle \ \ \ \ \ 2 \ \ \ 8$$
$$\displaystyle * \ \ \ *$$

The only place for the 7 is the far left bottom:

$$\displaystyle *$$
$$\displaystyle 6 \ \ \ *$$
$$\displaystyle * \ \ * \ \ *$$
$$\displaystyle \ \ \ \ \ 2 \ \ \ 8$$
$$\displaystyle 7 \ \ \ *$$

The only potential places for the 1 and the 3 are above the 6 and to the right of the 6.
This forces the 9 to go directly below the 6:

$$\displaystyle *$$
$$\displaystyle 6 \ \ \ *$$
$$\displaystyle 9 \ \ * \ \ *$$
$$\displaystyle \ \ \ \ \ 2 \ \ \ 8$$
$$\displaystyle 7 \ \ \ *$$

Numbers 1 and 3 are committed between two squares. We still need to place 4, 5, and 10. Look at the
square immediately to the right of the square that has 9 in it. It cannot be 10 or 5, because that would
violate the squares having 9 and 6 in them. So, it must be 4:

$$\displaystyle *$$
$$\displaystyle 6 \ \ \ *$$
$$\displaystyle 9 \ \ \ 4 \ \ \ *$$
$$\displaystyle \ \ \ \ \ 2 \ \ \ 8$$
$$\displaystyle 7 \ \ \ *$$

The rest of the numbers fall in place. The number above 4 must be 1 and the number above 6 must
be 3. The 5 must be directly below 2, and finally, 10 is to the right of 4:

$$\displaystyle 3$$
$$\displaystyle 6 \ \ \ 1$$
$$\displaystyle 9 \ \ \ 4 \ \ \ 10$$
$$\displaystyle \ \ \ \ \ 2 \ \ \ \ 8$$
$$\displaystyle 7 \ \ \ 5$$

Then, convert the numbers back to the letters of the alphabet.