College Algebra: eqn of line parallel to y=3x/2-7/9 thru (4,
- Thread starter chasann
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Re: College Algebra
Please show us your work/thoughts - so that we know where to begin to help you.
A line whose slope is "m" and passing through \(\displaystyle (x_1,y_1)\) will be described by following equation:
\(\displaystyle (y \, - \, y_1) \, = \, m \cdot (x \, - \,x_1)\)
chasann said:
Please show us your work/thoughts - so that we know where to begin to help you.
A line whose slope is "m" and passing through \(\displaystyle (x_1,y_1)\) will be described by following equation:
\(\displaystyle (y \, - \, y_1) \, = \, m \cdot (x \, - \,x_1)\)
skeeter
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Re: College Algebra
parallel lines have the same slope, so the first step is to identify the slope of the given line y= 3x/2- 7/9.
using this slope and the given point, (4,6), use the point-slope form of a linear equation to find the desired equation.
parallel lines have the same slope, so the first step is to identify the slope of the given line y= 3x/2- 7/9.
using this slope and the given point, (4,6), use the point-slope form of a linear equation to find the desired equation.