K killotin New member Joined Oct 17, 2005 Messages 3 Oct 17, 2005 #1 2^x+1 . 2^-2=1/8 This is part of the log functions chapter we are doing right now WORK DONE : I know that I have to get all the bases to be equal to 2 so I did 2^x+1 . 2^-2 = 1/2^3 Then I got stuck because of the fractions. Help :?:
2^x+1 . 2^-2=1/8 This is part of the log functions chapter we are doing right now WORK DONE : I know that I have to get all the bases to be equal to 2 so I did 2^x+1 . 2^-2 = 1/2^3 Then I got stuck because of the fractions. Help :?:
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Oct 17, 2005 #2 Hello, killotin! You were off to a good start . . . 2<sup>x+1</sup>·2<sup>-2</sup> .= .1/8 . Click to expand... We have: . 2<sup>x-1</sup> .= .1/2<sup>3</sup> .= .2<sup>-3</sup> . <--- There is the magic step! Equate exponents: . x - 1 .= .-3 . ---> . x = -2
Hello, killotin! You were off to a good start . . . 2<sup>x+1</sup>·2<sup>-2</sup> .= .1/8 . Click to expand... We have: . 2<sup>x-1</sup> .= .1/2<sup>3</sup> .= .2<sup>-3</sup> . <--- There is the magic step! Equate exponents: . x - 1 .= .-3 . ---> . x = -2
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Oct 17, 2005 #3 Multi-post. And another.
