Combination Question I don’t understand

Snickey

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The answer for Q 15, C is 42. But I don’t know how to get it. Plz help
 

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The answer for Q 15, C is 42. But I don’t know how to get it. Plz help
There are four classical CDs. So at least three means three or four.
He selects five. So include three or four classical and two or one other.
Look at this It seems 42 is incorrect.
 
I'm seeing the answer as 66 ways.

\(\displaystyle \dbinom{4}{3}\dbinom{6}{2}+\dbinom{4}{4}\dbinom{6}{1} = 66\)
 
Oh alright, I got the same answer too. Guess Cambridge got it wrong. Thanks everyone!
 
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