Combinations Probability

rachelmaddie

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Aug 30, 2019
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Hi. I need this checked please.
B25AB577-AB46-4322-85F2-0A3F77CF0ABE.jpeg
6)
Each of the 7 appetizers can be paired with one of the 10 entrees, and each entree can be paired with one of the 6 desserts.
P(A)
The possible outcome when a customer chooses appetizer: 7
P(E)
The possible outcome when a customer chooses entree: 10
P(D)
The possible outcome when a customer chooses dessert: 6
So the total different lunch specials is:
P(A) * P(E) * P(D)
Therefore, the number of combinations is: 7 * 10 * 6 = 420 different lunch specials
 
Your answer is correct. Side note: if this was my class, I'd advise against the P( ) notation.
 
I teach precalculus. I'd still advise against the notation, because P(A) can be interpreted as 'the probability of event A', when you really mean 'the number of ways that event A can happen'.
Then do you know a better way I could type it?
 
\(\#(P),~\|P\|.\text{ or }n(P)\)
I wouldn't use any of those. 'The total of ways to choose A is _________. The total of ways to choose B is __________........'. There really isn't notation for this concept. Your original post was excellent, except for the P( ) notation.
 
I wouldn't use any of those. 'The total of ways to choose A is _________. The total of ways to choose B is __________........'. There really isn't notation for this concept. Your original post was excellent, except for the P( ) notation.
Why not use any of those. Each is standard to denote the number of elements in a set. I have used each in my courses.
 
I wouldn't use any of those. 'The total of ways to choose A is _________. The total of ways to choose B is __________........'. There really isn't notation for this concept. Your original post was excellent, except for the P( ) notation.
n(A) is standard notation for the number of elements in set A as well as the others which pka listed.
 
I am sorry but I disagree with your answer. There are 8 choices for an appetizer, 11 choices for an entree and 7 choices for a dessert. Do you understand why?
 
No, I don’t understand why?
There may be 7 appetizer but there is always another choice---you can choose no appetizer! You can choose no entree (probably not since that is probability the greater cost) and (if you are on a diet for example) you can choose no dessert.
 
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