A aname New member Joined Dec 12, 2014 Messages 7 Dec 13, 2014 #1 What integral would I compare the integral above with to see if it converges or diverges? Thanks!
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Dec 14, 2014 #3 aname said: View attachment 4734 What integral would I compare the integral above with to see if it converges or diverges Click to expand... \(\displaystyle \dfrac{1}{{\sqrt {{\theta ^3} + 1} }} \le \dfrac{1}{{{\theta ^{3/2}}}}\)
aname said: View attachment 4734 What integral would I compare the integral above with to see if it converges or diverges Click to expand... \(\displaystyle \dfrac{1}{{\sqrt {{\theta ^3} + 1} }} \le \dfrac{1}{{{\theta ^{3/2}}}}\)
