A AsianGuy New member Joined Sep 4, 2013 Messages 1 Sep 4, 2013 #1 Given that (5+2i)/z = 2-i, find z in the form of a+bi I'm trying to teach my self FM and I got stuck on this. I don't want the whole solution just a hint on the first step. Last edited: Sep 4, 2013
Given that (5+2i)/z = 2-i, find z in the form of a+bi I'm trying to teach my self FM and I got stuck on this. I don't want the whole solution just a hint on the first step.
D Deleted member 4993 Guest Sep 4, 2013 #2 AsianGuy said: Given that (5+2i)/z = 2-i, find z in the form of a+bi I'm trying to teach my self FM and I got stuck on this. I don't want the whole solution just a hint on the first step. Click to expand... \(\displaystyle \displaystyle \frac{5+2i}{z} \ = 2 - i \) → \(\displaystyle \displaystyle \frac{5+2i}{2 - i} \ = z\) → \(\displaystyle \displaystyle \frac{5+2i}{2 - i} * \frac{2+ i}{2 + i}\ = z\) .... and continue....
AsianGuy said: Given that (5+2i)/z = 2-i, find z in the form of a+bi I'm trying to teach my self FM and I got stuck on this. I don't want the whole solution just a hint on the first step. Click to expand... \(\displaystyle \displaystyle \frac{5+2i}{z} \ = 2 - i \) → \(\displaystyle \displaystyle \frac{5+2i}{2 - i} \ = z\) → \(\displaystyle \displaystyle \frac{5+2i}{2 - i} * \frac{2+ i}{2 + i}\ = z\) .... and continue....
