X xxMsJojoxx Junior Member Joined Oct 6, 2020 Messages 54 Nov 1, 2020 #1 I can't figure out how to solve the beginning part f(x+h). This is how far I got: How do I 'plug in' to the equation? Attachments 1604263072273.png 4 KB · Views: 1
I can't figure out how to solve the beginning part f(x+h). This is how far I got: How do I 'plug in' to the equation?
X xxMsJojoxx Junior Member Joined Oct 6, 2020 Messages 54 Nov 1, 2020 #3 skeeter said: [MATH](x+h)^2 - x^2[/MATH] Click to expand... Thanks. But it's supposed to be one of the below answers. And I'm still not sure how I can get from to the correct multiple choice answer.
skeeter said: [MATH](x+h)^2 - x^2[/MATH] Click to expand... Thanks. But it's supposed to be one of the below answers. And I'm still not sure how I can get from to the correct multiple choice answer.
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Nov 1, 2020 #4 you have to expand [MATH](x+h)^2[/MATH] and combine like terms ...
X xxMsJojoxx Junior Member Joined Oct 6, 2020 Messages 54 Nov 1, 2020 #5 skeeter said: you have to expand [MATH](x+h)^2[/MATH] and combine like terms ... Click to expand... I finally got it. Thank you!
skeeter said: you have to expand [MATH](x+h)^2[/MATH] and combine like terms ... Click to expand... I finally got it. Thank you!
Steven G Elite Member Joined Dec 30, 2014 Messages 14,603 Nov 3, 2020 #6 I prefer to use the difference of squares rule: A^2 - B^2 = (A+B)(A-B). So (x+h)^2 - (x)^2 = ((x+h)+x)((x+h)-x)= (2x+h)(h)
I prefer to use the difference of squares rule: A^2 - B^2 = (A+B)(A-B). So (x+h)^2 - (x)^2 = ((x+h)+x)((x+h)-x)= (2x+h)(h)