A colony of bacteria numbers 100. If the population grows at a rate of 50% per hour, compounded hourly, what will it be in 8 hours?...

Plesae help me solve this. I've been at it for 2days now.... :roll:

Thanks a bunch!

AnG'

- Thread starter agreen37
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A colony of bacteria numbers 100. If the population grows at a rate of 50% per hour, compounded hourly, what will it be in 8 hours?...

Plesae help me solve this. I've been at it for 2days now.... :roll:

Thanks a bunch!

AnG'

This is no different than the growth of an amount of money in a bank.agreen37 said:A colony of bacteria numbers 100. If the population grows at a rate of 50% per hour, compounded hourly, what will it be in 8 hours?

A scecific deposit called the principal will grow to S = P(1 + i)^n.

In your case, P = 100, i = the periodic interest, or growth, rate, .50, and n = the number of compounding periods, 8.

Therefore, S = 100(1.5)^8 = 2562.89.

Denis said:or you can multiply 8 times:

100 * 1.5 * 1.5 * 1.5 * 1.5 * 1.5 * 1.5 * 1.5 * 1.5 = 2562.890625

TchrWill's 100 * (1.5)^8 is the same thing :idea: