tworitdash
New member
- Joined
- Aug 12, 2022
- Messages
- 10
I have the following function
x(k)=m∑Mei(Umk+βm)
Where
i=−1
And k is an integer.
The Um values come from a normal distribution and the βm values come from a uniform distribution.
Um∼N(μ,σ2)βm∼U(0,2π)
I want to know the conditional probability of both parameters μ and σ2 with each other.
Something like p(μ∣x,σ2) and p(σ2∣x,μ)
I have seen how people do it when x is a random number following a specific distribution. However, how to deal with this sum. I have attempted finding the distribution of the sum inside the function x, but I am almost unsuccessful. It can be found after the question. I know with central limit theorem (when M is large and σ is large), the distribution of x is a Gaussian distribution with mean 0 and standard deviation M/2 for both the real and the imaginary parts. However, how to find the statistics of x when M is still large but with not so big σ. So there are three cases:
1) M large and σ large - x becomes Gaussian with μx=0 and σx=M/2 for both real and imaginary
2) M large and σ−>0, the distribution of x becomes δ(1).
3) M large but σ reasonable - I want the distribution of x as a function of σ (and possibly μ).
Or, am I attempting the question in a wrong way? The original problem is to estimate μ and σ when some realizations ofx is available. Is it worth having an expression of the distribution of both real and imaginary parts ofx whenM is large in terms of μ and σ ? I was thinking of it because, in that case the conditional probabilities would be easier to find and any iterative technique can be used to estimate μ and σ.
What I have tried so far:
If I write the original model like this:
x(k)=m∑Am+iΓm
I have the distribution of α and γ.
They look like the following;
fA(α)=n=−∞∑+∞1−α21(fY(2(n+1)π−cos−1(α))−fY(2(n)π+cos−1(α)))
fΓ(γ)=n=−∞∑+∞1−α21(fY(2(n)π+sin−1(α))−fY((2n−1)π−sin−1(α)))
Where fY(y) is the density function of the random variableY=Uk+β , which is
fY(y)=4π1[erf(2kσkμ−y+2π)−erf(2kσkμ−y)]
x(k)=m∑Mei(Umk+βm)
Where
i=−1
And k is an integer.
The Um values come from a normal distribution and the βm values come from a uniform distribution.
Um∼N(μ,σ2)βm∼U(0,2π)
I want to know the conditional probability of both parameters μ and σ2 with each other.
Something like p(μ∣x,σ2) and p(σ2∣x,μ)
I have seen how people do it when x is a random number following a specific distribution. However, how to deal with this sum. I have attempted finding the distribution of the sum inside the function x, but I am almost unsuccessful. It can be found after the question. I know with central limit theorem (when M is large and σ is large), the distribution of x is a Gaussian distribution with mean 0 and standard deviation M/2 for both the real and the imaginary parts. However, how to find the statistics of x when M is still large but with not so big σ. So there are three cases:
1) M large and σ large - x becomes Gaussian with μx=0 and σx=M/2 for both real and imaginary
2) M large and σ−>0, the distribution of x becomes δ(1).
3) M large but σ reasonable - I want the distribution of x as a function of σ (and possibly μ).
Or, am I attempting the question in a wrong way? The original problem is to estimate μ and σ when some realizations ofx is available. Is it worth having an expression of the distribution of both real and imaginary parts ofx whenM is large in terms of μ and σ ? I was thinking of it because, in that case the conditional probabilities would be easier to find and any iterative technique can be used to estimate μ and σ.
What I have tried so far:
If I write the original model like this:
x(k)=m∑Am+iΓm
I have the distribution of α and γ.
They look like the following;
fA(α)=n=−∞∑+∞1−α21(fY(2(n+1)π−cos−1(α))−fY(2(n)π+cos−1(α)))
fΓ(γ)=n=−∞∑+∞1−α21(fY(2(n)π+sin−1(α))−fY((2n−1)π−sin−1(α)))
Where fY(y) is the density function of the random variableY=Uk+β , which is
fY(y)=4π1[erf(2kσkμ−y+2π)−erf(2kσkμ−y)]
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