A) Determine the constant of proportionality for the rate at which water is escaping.

B) Determine the rate at which the height is changing when the volume of water in the cone is changing at a rate of 1cm^3 per hour.

C) At some position, the water will cease to decrease, and the amount of water in the cone will stabilize. Find the height of the water in the cone when that happens.

My attempt:

A) This is probably wrong, but -> dV/dt = 10t-(he^kt) -> When V = π, -2t = 10t-(he^kt)

1/3π(h/3)^2 * h = π -> (h^3) /9 = 3 -> h=3, which I then plugged into the previous equation:

-2t = 10t-(3e^kt) -> 12t = 3e^kt -> k=(ln(4)+ln(t))/t, but I cant find k without t!

B) V = 1/3π(r^2) * h -> r/h = 5/15, so r=h/3 -> 1/3π((h^2) /9)*h

Taking the derivative: dV/dt = 1/9(πh^2) * (dh/dt) -> Given dV/dt = 1 -> 9/(πh^2) = dh/dt, but I can't find h without finding k and t!

C) dV/dt = 0 -> 0=10t-he^kt -> 10t = he^kt, but again, I can't find this without finding t and k!

Please help, I am very confused, and I know I am missing something here.