T TonyC New member Joined Aug 22, 2005 Messages 17 Aug 26, 2005 #1 I need help confirming an answer I have come up with: Equation for a Hyperbola with vertices: (2, 2/pi) and (-8, 3pi/2) r=16 over 3 +5sin(theta) :?
I need help confirming an answer I have come up with: Equation for a Hyperbola with vertices: (2, 2/pi) and (-8, 3pi/2) r=16 over 3 +5sin(theta) :?
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Aug 26, 2005 #2 I will confirm that your answer is a solution, but I would have said that just two vertices are not enough to determine a hyperbola.
I will confirm that your answer is a solution, but I would have said that just two vertices are not enough to determine a hyperbola.