- Thread starter mathdad
- Start date

- Status
- Not open for further replies.

- Joined
- Jan 29, 2005

- Messages
- 8,128

Yes indeed.The sum of 3 consecutive integers is 54. DO NOT SOLVE. Set up the needed equation....

Consecutive Integers:

x

x + 1

x + 2

x + (x + 1) + (x + 2) = 54

Yes?

- Joined
- Dec 30, 2014

- Messages
- 3,526

This way their sum will be (x-1)+x+(x+1) = 3x = 54. So x=18Note how after I did the addition I just had 3x, not for example 3x+7.

Using your method you get (x) + (x+1) + (x+2) = 3x+3 =54. Now you have to deal with the +3.

So 3x =51 and x=17

Can you explain that although both solutions are correct I have different values for x??

- Joined
- Apr 24, 2015

- Messages
- 711

Very good.

This way their sum will be (x-1)+x+(x+1) = 3x = 54. So x=18Note how after I did the addition I just had 3x, not for example 3x+7.

Using your method you get (x) + (x+1) + (x+2) = 3x+3 =54. Now you have to deal with the +3.

So 3x =51 and x=17

Can you explain that although both solutions are correct I have different values for x??

- Status
- Not open for further replies.