So I have an derivative of ds= tdt/(2t + 1)^1/2
when t=0, s=0
what is s when t=24?
I figured out my integral to be [(2t+1)^1/2]/2 + 1/(2(2t+1)^1/2) + C
The book answer is s= 54 but I cant seem to get there. Can anyone help?
\(\displaystyle \text{I have: }\:ds\:=\:\dfrac{t\,dt}{(2t+1)^{\frac{1}{2}}}\)
\(\displaystyle \text{When }t=0,\,s=0\)
\(\displaystyle \text{What is }s\text{ when }t=24\,?\)