K Kevice New member Joined Feb 24, 2021 Messages 2 Feb 24, 2021 #1 I need to find the value of a and b if the function has a continuity in x =2, I tried finding it but I just can't figure out how
I need to find the value of a and b if the function has a continuity in x =2, I tried finding it but I just can't figure out how
K Kevice New member Joined Feb 24, 2021 Messages 2 Feb 24, 2021 #2 Here is the problem I got: I need to find a & b if it is continuous in x = 2, this is where I'm stuck at , I don't know what else to do Attachments 215368.jpg 69.2 KB · Views: 2
Here is the problem I got: I need to find a & b if it is continuous in x = 2, this is where I'm stuck at , I don't know what else to do
D Deleted member 4993 Guest Feb 25, 2021 #3 Kevice said: Here is the problem I got: View attachment 25345 I need to find a & b if it is continuous in x = 2, this is where I'm stuck at , I don't know what else to do Click to expand... If values of 'a' and 'b' are such that ax2 + bx - 4 is exactly divisible by (x-2) and f(2-) = -6 then the discontinuity of (ax2 + bx - 4)/(x - 2) at x =2 will be removed
Kevice said: Here is the problem I got: View attachment 25345 I need to find a & b if it is continuous in x = 2, this is where I'm stuck at , I don't know what else to do Click to expand... If values of 'a' and 'b' are such that ax2 + bx - 4 is exactly divisible by (x-2) and f(2-) = -6 then the discontinuity of (ax2 + bx - 4)/(x - 2) at x =2 will be removed
Steven G Elite Member Joined Dec 30, 2014 Messages 14,603 Feb 25, 2021 #4 You factored the numerator incorrectly. I would do long division to factor that numerator so that one of the factors is (x-2).
You factored the numerator incorrectly. I would do long division to factor that numerator so that one of the factors is (x-2).