R roxstar1 New member Joined Oct 25, 2005 Messages 34 May 14, 2006 #1 could someone please point me in the right direction on this problem? determine the convergence/divergence of the series infinity E 1/[n(ln n)^2] n=2
could someone please point me in the right direction on this problem? determine the convergence/divergence of the series infinity E 1/[n(ln n)^2] n=2
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 May 14, 2006 #2 Hello, roxstar1! Could someone please point me in the right direction on this problem? Determine the convergence/divergence of the series; \(\displaystyle \L\;\sum^{\infty}_{n=2}\,\frac{1}{n(\ln n)^2\) Click to expand... Use the integral test . . . We have: \(\displaystyle \L\;\int^{\;\;\;\infty}_2\frac{dx}{x(\ln x)^2} \;= \;\int^{\;\;\;\infty}_2\frac{1}{x}\)\(\displaystyle \cdot\left(\ln x\right)^{-2}\,dx\) and let \(\displaystyle u\,=\,\ln x\)
Hello, roxstar1! Could someone please point me in the right direction on this problem? Determine the convergence/divergence of the series; \(\displaystyle \L\;\sum^{\infty}_{n=2}\,\frac{1}{n(\ln n)^2\) Click to expand... Use the integral test . . . We have: \(\displaystyle \L\;\int^{\;\;\;\infty}_2\frac{dx}{x(\ln x)^2} \;= \;\int^{\;\;\;\infty}_2\frac{1}{x}\)\(\displaystyle \cdot\left(\ln x\right)^{-2}\,dx\) and let \(\displaystyle u\,=\,\ln x\)
R roxstar1 New member Joined Oct 25, 2005 Messages 34 May 14, 2006 #3 Thanks..i didnt think about using that test