convert 'sec(arctan4x)' into an algebra form

Re: sec(arctan4x)

icyhot2590 said:
converting into an algebraic form


sec(arctan4x)

would it be

sec(4/(1+(3x)^2)

no.

let y = arctan(4x) ... then tan(y) = 4x/1 = opposite/adjacent

using Pythagoras ... hypotenuse = sqrt(1 + 16x<sup>2</sup>)

sec(y) = hypotenuse/adjacent = sqrt(1 + 16x<sup>2</sup>)
 
icyhot2590 said:
would it be sec(4/(1+(3x)^2)
How did you arrive at this answer?

Please reply showing all of your work and reasoning. Thank you.

Eliz.
 
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