#### Mohssine

##### New member
ABCD is a convex quadrilateral which AD=AB+CD, P is the intersection of the two bisector or the two angles BAD and ADC, proof that PA=PC

#### Subhotosh Khan

##### Super Moderator
Staff member
ABCD is a convex quadrilateral which AD=AB+CD, P is the intersection of the two bisector or the two angles BAD and ADC, proof that PA=PC
Please show us what you have tried and exactly where you are stuck.

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#### Mohssine

##### New member
its a geometry classic exercise is anyone has an idea he is welcome to comment

#### Dr.Peterson

##### Elite Member
ABCD is a convex quadrilateral which AD=AB+CD, P is the intersection of the two bisector of[?] the two angles BAD and ADC, proof that PA=PC
If this is what you mean, then the claim is false:

#### Mohssine

##### New member
Sorry i mean BP=CP

#### Dr.Peterson

##### Elite Member
You told me privately that it should be BP = CP. Here's the new drawing, and a line (green) that you may find helpful: