Convex quadrilateral ABCD which AD=AB+CD

Mohssine

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ABCD is a convex quadrilateral which AD=AB+CD, P is the intersection of the two bisector or the two angles BAD and ADC, proof that PA=PC
 

Subhotosh Khan

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ABCD is a convex quadrilateral which AD=AB+CD, P is the intersection of the two bisector or the two angles BAD and ADC, proof that PA=PC
Please show us what you have tried and exactly where you are stuck.

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Please share your work/thoughts about this problem.
 

Mohssine

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its a geometry classic exercise is anyone has an idea he is welcome to comment
 

Dr.Peterson

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ABCD is a convex quadrilateral which AD=AB+CD, P is the intersection of the two bisector of[?] the two angles BAD and ADC, proof that PA=PC
If this is what you mean, then the claim is false:
1613957172062.png
Please correct the problem.
 

Mohssine

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Sorry i mean BP=CP
 

Dr.Peterson

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You told me privately that it should be BP = CP. Here's the new drawing, and a line (green) that you may find helpful:

1613966726217.png
 
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