Correct Me If I Am Wrong? Formula Problem.

S

SCSmith

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Oct 25, 2005
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S = C/1 - M; M
(1 - M)S = (1 -M)(C/1 - M)
(1 - M)S = C
S - SM = C
S - S -SM = C - S
-SM = C - S
-SM/-S = C - S/-S
M = C -S/-S[/url][/code][/u]
 
I don't watch CSI so my forensic abilities* on this
S = C/1 - M; M
(1 - M)S = (1 -M)(C/1 - M)
Click to expand...
are limited.

I can't, infact, go beyond the first line:

\(\displaystyle S = \frac{C}{1-M}; \, M\)

What is the semi-colon meant to be? Or if it's meant to be a semi-colon, why is it there?

* To steal one of Soroban's clever analogies.
 
I do watch CSI, but...

Might this equation actually have been:

. . . . .S = C/(1 - M)

(Note the parentheses.) And might the instructions (not including in your post) have been:

. . . . .Solve the equation for the variable "M".

Do you mean your final equation to be:

. . . . .M = (S - C)/S

(Note the parentheses, and the handling of that "minus" sign in the denominator.)

If so, then your solution is correct. If not, please reply with the full text of the exercise (and its instructions), using grouping symbols to make your meaning clear.

Thank you.

Eliz.
 
SCSmith said:
S = C/1 - M; M
(1 - M)S = (1 -M)(C/1 - M)
(1 - M)S = C
S - SM = C
S - S -SM = C - S
-SM = C - S
-SM/-S = C - S/-S
M = C -S/-S[/url][/code][/u]
Click to expand...
Look, Mr Smith, try to be CLEAR!
From what you've done, your "S = C/1 - M; M" should be typed like this:
S = 1 / (1 - M) ; solve for M

S(1 - M) = C : multiply by (1 - M)
1 - M = C / S : divide by S
M - 1 = -C / S : multiply by -1
M = 1 - C/S : add 1
 
Note:

. . .M = (S - C)/S

. . . . .= (S/S) - (C/S)

. . . . .= 1 - (C/S)

That is to say, the two solutions are equivalent.

Eliz.
 
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