cos theta = a dot b / magnitude of a multiply magnitude of b

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wine

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I do cos theta = a dot b / magnitude of a multiply magnitude of b and find the angle is 11.3 degree
then i get the BN as 1.17 which when i check it NC will be over AC.
Can you help me with this please!!Thank you.
 
wine said:
View attachment 5362
I do cos theta = a dot b / magnitude of a multiply magnitude of b and find the angle is 11.3 degree
then i get the BN as 1.17 which when i check it NC will be over AC.
Can you help me with this please!!Thank you.
Click to expand...

It would be really great if you would post readable questions.
 
I think the first image contains the following:

Parallelogram OBCA has its sides determined by \(\displaystyle \, \overrightarrow{OA}\, =\, \overrightarrow{a}\, =\, [4,\, 2,\, 4]\,\) and \(\displaystyle \, \overrightarrow{OB}\, =\, \overrightarrow{b}\, =\, [3,\, 1,\, 4].\) A line is drawn from B perpendicular to side AC of the parallelogram to intersect AC at N. Determine the length of BN.

I'm not going to try to dissect sideways stuff, though. Sorry. ;)
 
i understand the question but i dont know how to answer it :(
 
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