Cos(theta - pi/2)

[NEHA]

Cos(theta - pi/2)

Cos(A - B)
Cos(A - B) = CosA CosB + SinA SinB
A with theta and B with pi/2
Cos(theta - pi/2) = Cos theta Cos pi/2 + Sin theta Sin pi/2
Cos(pi/2) is 0 and Sin(pi/2) is 1
Cos(theta - pi/2) = Cos theta)(0) + (Sin theta)(1) = Sin theta which is the answer


I am not sure....i'm in the middle of this...saying yes or no...
am i correct

 

[stapel]

am i correct

I don't know. You posted an expression, but what's the question?

Thank you.

Eliz.

 

[NEHA]

am i correct

I don't know. You posted an expression, but what's the question?

Thank you.

Eliz.

i have to simplify:
Cos(theta - pi/2)

 

[stapel]

Look at the graph of cosine. What do you get, if you shift this graph to the right by pi/2?

Eliz.