RedheadSTL
New member
- Joined
- Aug 14, 2006
- Messages
- 7
Thanks in advance!
1) 2 SQRT (x + 1) = 6
2) SQRT(3x^2 - 9) = 2x
3) [sqrt(x) + 1] / [sqrt(x) – 1] + [sqrt(x) – 1] / [sqrt(x) + 1]
1) 2 SQRT (x + 1) = 6
2) SQRT(3x^2 - 9) = 2x
3) [sqrt(x) + 1] / [sqrt(x) – 1] + [sqrt(x) – 1] / [sqrt(x) + 1]