K K_Swiss New member Joined Feb 8, 2008 Messages 28 Feb 27, 2008 #1 Cross Product : Prove that | a × b | = . . . Prove that | a × b | = ? [(a • b)(b • b) - (a • b)²] | a × b | = | a || b|sinx I don't know how to prove it. . .
Cross Product : Prove that | a × b | = . . . Prove that | a × b | = ? [(a • b)(b • b) - (a • b)²] | a × b | = | a || b|sinx I don't know how to prove it. . .
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Feb 28, 2008 #2 Re: Cross Product : Prove that | a × b | = . . . Use the two identities . \(\displaystyle \begin{array}{l}\left( {A \times B} \right)\cdot \left({C\times D} \right)=\left( {A \cdot C}\right)\left({B \cdot D}\right)-\left({A \cdot D}\right)\left({B \cdot C} \right)\\\left\|{A\times B}\right\|^2=\left( {A\times B} \right)\cdot\left( {A\times B}\right)\\\end{array}\)
Re: Cross Product : Prove that | a × b | = . . . Use the two identities . \(\displaystyle \begin{array}{l}\left( {A \times B} \right)\cdot \left({C\times D} \right)=\left( {A \cdot C}\right)\left({B \cdot D}\right)-\left({A \cdot D}\right)\left({B \cdot C} \right)\\\left\|{A\times B}\right\|^2=\left( {A\times B} \right)\cdot\left( {A\times B}\right)\\\end{array}\)