TheAngryMathStudent
New member
- Joined
- Feb 28, 2014
- Messages
- 4
Long story short, had assignment which I had to re-do over easter, but because I
had pre-ordered tickets I'm only going back tonight and the 2nd attempt is due
tomorrow. Since I don't have access to anyone else, I turn to you guys. I
thought I'd make it by now, but I'm not gonna work it out on my
own.
A curve is given by
x(t) = 3(t - sin(t))
y(t) = 3(1- cos(t))
Find the parameterized "normalcurve" x(s;t); y(s;t) that
goes through (x(t); y(t)) where s is the parameter to
"normalcurve"
(I don't know the English Word for it, but
normalcurve is the 90 degree angle of a line, I'm not quite sure how to
formulate it?)
I've drawn up the curve. I figured if I managed to
calculate the curve that's opposite (lowpoint where the other one has highpoint)
then that curve would
it? Kinda like a wildshot too be quite honest.
had pre-ordered tickets I'm only going back tonight and the 2nd attempt is due
tomorrow. Since I don't have access to anyone else, I turn to you guys. I
thought I'd make it by now, but I'm not gonna work it out on my
own.
A curve is given by
x(t) = 3(t - sin(t))
y(t) = 3(1- cos(t))
Find the parameterized "normalcurve" x(s;t); y(s;t) that
goes through (x(t); y(t)) where s is the parameter to
"normalcurve"
(I don't know the English Word for it, but
normalcurve is the 90 degree angle of a line, I'm not quite sure how to
formulate it?)
I've drawn up the curve. I figured if I managed to
calculate the curve that's opposite (lowpoint where the other one has highpoint)
then that curve would
it? Kinda like a wildshot too be quite honest.
Last edited by a moderator: