D Dorian Gray Junior Member Joined Jan 20, 2012 Messages 143 Mar 13, 2012 #1 Greetings everyone, I need to sketch the following function y= x^3 + x However, I seem to be having issues finding the critical values. I always end up with imaginary numbers. I attached a copy of my work. Any help or guidance is greatly appreciated.
Greetings everyone, I need to sketch the following function y= x^3 + x However, I seem to be having issues finding the critical values. I always end up with imaginary numbers. I attached a copy of my work. Any help or guidance is greatly appreciated.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Mar 13, 2012 #2 That simply means it has no critical values.
D Dorian Gray Junior Member Joined Jan 20, 2012 Messages 143 Mar 14, 2012 #3 Thank you Thank you both for your input! It is greatly appreciated @JeffM. Well the derivative would be 3x^2 +1, therefore the graph is always increasing from negative infinity to positive infinity. Last edited: Mar 14, 2012
Thank you Thank you both for your input! It is greatly appreciated @JeffM. Well the derivative would be 3x^2 +1, therefore the graph is always increasing from negative infinity to positive infinity.
D Deleted member 4993 Guest Mar 14, 2012 #4 And the slope always >1 (and exists everywhere) → hence slope never = 0 and Critical Point does not exist
And the slope always >1 (and exists everywhere) → hence slope never = 0 and Critical Point does not exist