d'Alembert Formula

pdestud

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Use d'Alembert's solution of the wave equation to find the solution of

[MATH]\frac{\partial^2 u}{\partial x^2} = \frac{\partial^2 u}{\partial t^2} \qquad (t \geq 0, x \geq 0) [/MATH]
[MATH] \frac{\partial u(0,t)}{\partial t} = \alpha \frac{\partial u(0,t)}{\partial x} \qquad (t \geq 0) [/MATH]
[MATH] u(x,0) = \phi_0 (x) \qquad (x \geq 0) [/MATH]
[MATH] \frac{\partial u}{\partial t} (x, 0) = \phi_1 (x) \qquad (x \geq 0) [/MATH]
where [MATH] \alpha \neq -1 [/MATH] is a constant and [MATH] \phi_0 (x) [/MATH] and [MATH] \phi_1 (x) [/MATH] are twice continuously differentiable for [MATH] x > 0 [/MATH] and vanish near [MATH] x = 0 [/MATH]. Show that in general no solution exists when [MATH] \alpha = -1 [/MATH].
 
Use d'Alembert's solution of the wave equation to find the solution of

[MATH]\frac{\partial^2 u}{\partial x^2} = \frac{\partial^2 u}{\partial t^2} \qquad (t \geq 0, x \geq 0) [/MATH]
[MATH] \frac{\partial u(0,t)}{\partial t} = \alpha \frac{\partial u(0,t)}{\partial x} \qquad (t \geq 0) [/MATH]
[MATH] u(x,0) = \phi_0 (x) \qquad (x \geq 0) [/MATH]
[MATH] \frac{\partial u}{\partial t} (x, 0) = \phi_1 (x) \qquad (x \geq 0) [/MATH]
where [MATH] \alpha \neq -1 [/MATH] is a constant and [MATH] \phi_0 (x) [/MATH] and [MATH] \phi_1 (x) [/MATH] are twice continuously differentiable for [MATH] x > 0 [/MATH] and vanish near [MATH] x = 0 [/MATH]. Show that in general no solution exists when [MATH] \alpha = -1 [/MATH].
Please share your work/thoughts about this assignment.

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How is this problem different from the "almost" duplicate problem you posted at:

https://www.freemathhelp.com/forum/threads/dalemberts-solution-of-wave-equation.118385/
 
2ux2=2ut2(t0,x0)\displaystyle \frac{\partial^2 u}{\partial x^2} = \frac{\partial^2 u}{\partial t^2} \qquad (t \geq 0, x \geq 0)

u(0,t)t=αu(0,t)x(t0)\displaystyle \frac{\partial u(0,t)}{\partial t} = \alpha \frac{\partial u(0,t)}{\partial x} \qquad (t \geq 0)

u(x,0)=ϕ0(x)(x0)\displaystyle u(x,0) = \phi_0 (x) \qquad (x \geq 0)

ut(x,0)=ϕ1(x)(x0)\displaystyle \frac{\partial u}{\partial t} (x, 0) = \phi_1 (x) \qquad (x \geq 0)

where α1\displaystyle \alpha \neq -1 is a constant and ϕ0(x)\displaystyle \phi_0 (x) and ϕ1(x)\displaystyle \phi_1 (x) are twice continuously differentiable for x>0\displaystyle x > 0 and vanish near x=0\displaystyle x = 0 . Show that in general no solution exists when α=1\displaystyle \alpha = -1 .

Now I can read your code.
 
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