# Davied has less than one-half the number of balloons that kaite has .

#### mariam90

##### New member
1. Davied has less than one-half the number of balloons that kaite has . If David has d balloons and kite has K balloons has ,which of the following equations correctly express the relationships between d and k.
a. d= 1/2 (k+4)
b. d= 1/2 (k-4)
c. d= 1/2 k+4
d.d= 1/2 k-4
e. d=2 k-4

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#### Subhotosh Khan

##### Super Moderator
Staff member
1. Davied has less than one-half the number of balloons that kaite has . If David has d balloons and kite has K balloons has ,which of the following equations correctly express the relationships between d and k.
a. d= 1/2 (k+4)
b. d= 1/2 (k-4)
c. d= 1/2 k+4
d.d= 1/2 k-4
e. d=2 k-4
What are your thoughts?

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#### Dr.Peterson

##### Elite Member
1. Davied has less than one-half the number of balloons that kaite has . If David has d balloons and kite has K balloons has ,which of the following equations correctly express the relationships between d and k.
a. d= 1/2 (k+4)
b. d= 1/2 (k-4)
c. d= 1/2 k+4
d.d= 1/2 k-4
e. d=2 k-4
I think you have copied the question incorrectly. Clearly you misspelled the names (so that each is spelled in two different ways); also you omitted a number, since as stated this would be an inequality ("__ is less than __"), not an equation ("__ is 4 less than __"). Copying incorrectly can make it impossible to solve a problem.

I think the correct question is this:

1. David has 4 less than one-half the number of balloons that Kate has . If David has d balloons and Kate has k balloons, which of the following equations correctly expresses the relationship between d and k?
a. d= 1/2 (k + 4)
b. d= 1/2 (k - 4)
c. d= 1/2 k + 4
d. d= 1/2 k - 4
e. d= 2k - 4

Is that correct?

Now, what do you think the answer might be, and why? By showing your thoughts, you give us a chance to identify where you are having trouble, and help you better. We don't just give answers.

#### Dr.Peterson

##### Elite Member
For clarity, problem could be presented this way:

If d < k/2, which of the following equations correctly
express the relationships between d and k?
1: d = (1/2) * (k+4)
2: d = (1/2) * (k-4)
3: d = (1/2)*k + 4
4: d = (1/2)*k - 4
5: d = 2*k - 4

Unless I goofed up, 2 of the equations are applicable.
If I'm wrong about a 4 having been dropped from the question, then it is still worded incorrectly. None of the equations "correctly express the relationships"; two of them are possible relationships (that is, are compatible with the inequality), but we can't say that any of them are necessarily correct.

#### mariam90

##### New member
mariam90

sorry or replying late i have problem with internet connection i there any formula for solving this question i am confused between "a " and "d" .

#### mariam90

##### New member
After a couple coffees, I fully agree with "4" having been dropped
the way you describe it.
Results in d = k/2 - 4
Then only one of the 5 choices is correct.
Thanks Dr.P.

Denis can you explain it to me I am confused between b and d.

#### Dr.Peterson

##### Elite Member
sorry or replying late i have problem with internet connection i there any formula for solving this question i am confused between "a " and "d" .
Can you confirm my guess that it really said this?

David has 4 less than one-half the number of balloons that Kate has . If David has d balloons and Kate has k balloons, which of the following equations correctly expresses the relationship between d and k?

Denis pointed out the difference in the symbols; to match that with the English, you need to look at how the words link together. You have:

David has 4 less than one-half the number of balloons that Kate has

That is,

d is 4 less than one-half of k

There is a subtraction (4 less) and a multiplication (1/2 of). Which should be done first?

Suppose you start with k. What will you do to find the value of d?

#### mariam90

##### New member
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#### Dr.Peterson

##### Elite Member
So, are you satisfied with the answer?

If not, please tell us your own thinking about it, so we can see whether you still need help with it.