(3-i)^6

r=square root of 10

a=r cos alpha

alpha=3/square root of 10

alpha=18.43494882

I have done this and similar problems over and over and can't figure out how they get alpha= -18.43493882

- Thread starter vanalm
- Start date

(3-i)^6

r=square root of 10

a=r cos alpha

alpha=3/square root of 10

alpha=18.43494882

I have done this and similar problems over and over and can't figure out how they get alpha= -18.43493882