C cmnalo Junior Member Joined Nov 5, 2006 Messages 61 Dec 6, 2006 #1 ∫(t-t^2)^2dt interval(0,1) u= t-t^2 du = 1-2tdt dt = du /1-2t ∫(u)^2dt ∫ (u)^2 (du/1-2t) I'm having trouble with the next step. U^2 would become 1/3(u)^3 but how do I deal with the du/1-2t?
∫(t-t^2)^2dt interval(0,1) u= t-t^2 du = 1-2tdt dt = du /1-2t ∫(u)^2dt ∫ (u)^2 (du/1-2t) I'm having trouble with the next step. U^2 would become 1/3(u)^3 but how do I deal with the du/1-2t?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Dec 6, 2006 #2 you can't do this definite integral using substitution. expand (t - t<sup>2</sup>)<sup>2</sup>, then integrate.
you can't do this definite integral using substitution. expand (t - t<sup>2</sup>)<sup>2</sup>, then integrate.
