Derivative: f' = 1/x, but how do I find second deriv?

[Tazman]

I have a problem where it asks me to find the f' - of a problem, which I figured out to be 1/x.

But now I need to find second derivative of 1/x.

Would f" still be 1/x? Truly not sure of my answer

Thx for help. Taz

 

[o_O]

Re: Derivaties 1/x

Imagine:
\(\displaystyle \frac{1}{x} = x^{-1}\)

And use your power rules. Does that help?

 

[Tazman]

Re: Derivaties 1/x

Imagine:
\(\displaystyle \frac{1}{x} = x^{-1}\)

And use your power rules. Does that help?

So i got -1/x^2

 

[o_O]

Re: Derivaties 1/x

Good job :wink:

So I'm guessing your original function was f(x) = lnx or something close?

 

[Tazman]

Re: Derivaties 1/x

Thanks a mil o!!