Frankyannehhh
New member
- Joined
- Sep 8, 2020
- Messages
- 4
A rectangular lot has an area of 1600 sq. m. Find the least amount of fence that could be used to emclose the area
sol:
let x and t the dimensions of the lot
area : xy = 1600 sq.m
y = 1600/x
perimeter: 2(x+y)
= 2(x+1600/x)
now i used the derivative test
p'(x) = 2-(3200/x²) =0
= 3200 = 2x²
= x² = 1600
= 40
and now i'm stuck and dont know what to do. Ive searched across the internet and found out that the answer is 160m but im not sure if its correct
sol:
let x and t the dimensions of the lot
area : xy = 1600 sq.m
y = 1600/x
perimeter: 2(x+y)
= 2(x+1600/x)
now i used the derivative test
p'(x) = 2-(3200/x²) =0
= 3200 = 2x²
= x² = 1600
= 40
and now i'm stuck and dont know what to do. Ive searched across the internet and found out that the answer is 160m but im not sure if its correct