Derive maximum for normal distribution?

[mwedwards]

Given the sum of all Y over a 24-hour period (t = -12..12), knowing the distribution of that metric over that period roughly corresponds to a gaussian normal distribution N(0, sigma^2), and knowing the std. deviation, is it possible to compute the maximum for this distribution (t=0)?

Y = 54000
sigma^2 = 4.5 hours

Please let me know if I have underspecified the problem, or if any additional clarifications are required.

 

[tkhunny]

The Normal Distribution has no inherent maximum or minimum. You'll have to try something else. q.v. Truncated Normal (for example)