Apprentice123
New member
- Joined
- Sep 2, 2008
- Messages
- 22
To determine the equation of cylindrical surface whose guideline is the curve (s) and the geratrizes are parallel to the straight (r). Building the surface
(s):
\(\displaystyle -4x^2+z^2=16\)
\(\displaystyle y=2\)
(r):
\(\displaystyle x=2z\)
\(\displaystyle y=-z+1\)
I have the parametric equations:
\(\displaystyle X=x+2t\)
\(\displaystyle Y=y-t\)
\(\displaystyle Z=z+t\)
Replace the equations of the guideline
\(\displaystyle t=y-2\)
\(\displaystyle 4x^2+15y^2-z^2+16xy-2yz-32x-60y+4z+76=0\)
The Equation i find. Now how to build the surface?
(s):
\(\displaystyle -4x^2+z^2=16\)
\(\displaystyle y=2\)
(r):
\(\displaystyle x=2z\)
\(\displaystyle y=-z+1\)
I have the parametric equations:
\(\displaystyle X=x+2t\)
\(\displaystyle Y=y-t\)
\(\displaystyle Z=z+t\)
Replace the equations of the guideline
\(\displaystyle t=y-2\)
\(\displaystyle 4x^2+15y^2-z^2+16xy-2yz-32x-60y+4z+76=0\)
The Equation i find. Now how to build the surface?
