pretzel1998
New member
- Joined
- Jan 4, 2015
- Messages
- 4
Hi There!
This is my first time posting on this forums, so I hope im following the right etiquette.
Im having some severe difficulties with the problems under Question 3 in this past exam paper. http://www.nzqa.govt.nz/nqfdocs/ncea-resource/exams/2014/91267-exm-2014.pdf
Can someone please check my answers and explain the questions where I faceplanted? Thanks
3. (a), I got 1/9 which im pretty sure is good.
3. (b), I got 2/3 which im pretty sure is good.
3. (c,i). I got 1/81, im not very confident about this answer because the wording of the question is incredibly bad. I did 4/36 X 4/36 as that's the probability he gets 5 on the first roll, and then 5 on the second roll to win?
3. (c,ii). I got 13/1458, I don't think I got this right because it seems like such a crazy probability. I did the probability he got the sum of 5 on the first roll (4/36), multiplied by the probability that he did not get a sum of 5 on the second roll (13/18 I think??? I might be wrong), the multiplied again by the probability that he will get a sum of 5. so in total (4/36 X 13/18 X 4/36 = 13/1458)???? Really confused about this question.
3. (d) This question I had absolutely no idea what to do. I some how got 7/18, but I think im wrong.
Thanks so much!
This is my first time posting on this forums, so I hope im following the right etiquette.
Im having some severe difficulties with the problems under Question 3 in this past exam paper. http://www.nzqa.govt.nz/nqfdocs/ncea-resource/exams/2014/91267-exm-2014.pdf
Can someone please check my answers and explain the questions where I faceplanted? Thanks
3. (a), I got 1/9 which im pretty sure is good.
3. (b), I got 2/3 which im pretty sure is good.
3. (c,i). I got 1/81, im not very confident about this answer because the wording of the question is incredibly bad. I did 4/36 X 4/36 as that's the probability he gets 5 on the first roll, and then 5 on the second roll to win?
3. (c,ii). I got 13/1458, I don't think I got this right because it seems like such a crazy probability. I did the probability he got the sum of 5 on the first roll (4/36), multiplied by the probability that he did not get a sum of 5 on the second roll (13/18 I think??? I might be wrong), the multiplied again by the probability that he will get a sum of 5. so in total (4/36 X 13/18 X 4/36 = 13/1458)???? Really confused about this question.
3. (d) This question I had absolutely no idea what to do. I some how got 7/18, but I think im wrong.
Thanks so much!