# did i do somethin' wrong?????????

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#### Guest

##### Guest
i got this problem:3x^3-6x^2-24x
it says to factor it, well, i got the common factor 3x and i ended up with
3x(x-2x-8x) what did i do wrong? or did i do somethin' wrong?
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#### ibueno1

##### New member
yes you did something wrong that is not the right answer

find two numbers whose product equals 3
and find two products whose product equals 24

multiply all the possible factorizations
until you get the middle number

#### sgrabbit

##### New member
you did do something wrong you havent factored from everything.your answer should have been:3x(x^2-2x-8).thats what it should have been.

#### JOSE JAIME-RODRIGUEZ

##### New member
here is the problem: 3x^3-6x^2-24x

....you got the common factor right which is 3x.
you have divide 3x into all the three numbers and it will look like this:
..................3x(x^2-2x-8)

next you simplify it and it will look something like this:
..................3x (x-4) (x+2)