G Guest Guest Nov 1, 2005 #1 Solve for x: 4 ^x = 256. x = a. -1/2 b. 1/2 c. 3/2 d. 5/2 e. 7/2 f. 9/2 g. 11/2 h. none of these IS THIS RIGHT
Solve for x: 4 ^x = 256. x = a. -1/2 b. 1/2 c. 3/2 d. 5/2 e. 7/2 f. 9/2 g. 11/2 h. none of these IS THIS RIGHT
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,579 Nov 1, 2005 #2 Write each side as a power of 2. Then compare the powers, and solve for x. If you get stuck, please reply showing how far you have gotten. For instance, 4 = 2<sup>?</sup>, and 256 = 2<sup>??</sup>, and so forth. Thank you. Eliz.
Write each side as a power of 2. Then compare the powers, and solve for x. If you get stuck, please reply showing how far you have gotten. For instance, 4 = 2<sup>?</sup>, and 256 = 2<sup>??</sup>, and so forth. Thank you. Eliz.
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Nov 1, 2005 #3 Hello, achillesg22! Solve for \(\displaystyle x:\;\;4 ^x \:= \:256\) \(\displaystyle (a)\;-\frac{1}{2}\qquad\qquad(b)\;\frac{1}{2}\qquad\qquad(c)\;\frac{3}{2}\qquad\qquad(d)\;\frac{5}{2}\qquad\qquad(e)\;\frac{7}{2}\qquad\qquad(f)\;\frac{9}{2}\qquad\qquad(g)\;\frac{11}{2}\) . . . . . . . . \(\displaystyle (h)\;\text{none of these}\) , <--- IS THIS RIGHT? Click to expand... Yes . . . We have: .\(\displaystyle 4^x \:= \:4^4\qquad\longrightarrow\qquad x \,= \,4\)
Hello, achillesg22! Solve for \(\displaystyle x:\;\;4 ^x \:= \:256\) \(\displaystyle (a)\;-\frac{1}{2}\qquad\qquad(b)\;\frac{1}{2}\qquad\qquad(c)\;\frac{3}{2}\qquad\qquad(d)\;\frac{5}{2}\qquad\qquad(e)\;\frac{7}{2}\qquad\qquad(f)\;\frac{9}{2}\qquad\qquad(g)\;\frac{11}{2}\) . . . . . . . . \(\displaystyle (h)\;\text{none of these}\) , <--- IS THIS RIGHT? Click to expand... Yes . . . We have: .\(\displaystyle 4^x \:= \:4^4\qquad\longrightarrow\qquad x \,= \,4\)