Let g(x)=x^(2)*sqrt(f(x)) where f is a differentiable function such that f(1)=4 and f'(1)=1. Find g'(1). The answer if 17/4.
so far I solved for g'(x) which I believe comes to 2x*sqrt(f(x))+x^2*d/dx*f(x)/2*sqrt(f(x))
and then I tried to sub in the given. so I subbed 1 into every x I see but can't seem to come to the final answer?
so far I solved for g'(x) which I believe comes to 2x*sqrt(f(x))+x^2*d/dx*f(x)/2*sqrt(f(x))
and then I tried to sub in the given. so I subbed 1 into every x I see but can't seem to come to the final answer?