Differential equation
- Thread starter mimie
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Harry_the_cat
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In doing the first part you would have found c and k, yes?
Sub them back in and isolate x.
Can you show your working for (a)? And I'll show you how to put it together. The "hard" part is done in part (a).
Sub them back in and isolate x.
Can you show your working for (a)? And I'll show you how to put it together. The "hard" part is done in part (a).
HallsofIvy
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Presumably, in order to do (a) you solved the differential equation. To get (b), replace the "k" in that solution with the value, (2/hT)ln(5/2), you found in (a).