Daniel Garla Pismel
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- Joined
- Apr 13, 2021
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- 6
Sorry about the rules, I didn't know about them. Will consider in the next timeFirst define variables.
Since you need to calculate "time" for "liquid to flow" - define
Time required = t min (minute)
Then other unknown is flowrate. Assume:
F12 (L/min)= flow rate from tank 1 to 2 = 2 L/min, and
F21 (L/min)= flow rate from tank 2 to1 = = 2 L/min
Continue.....
Please show us what you have tried and exactly where you are stuck.
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Assume that:Sorry about the rules, I didn't know about them. Will consider in the next time
I tried to use the flow rate from tank to tank, but I got nowhere because of the numbers the exercise gave.
Considering x1 the amount of fertilizer in T1 and x2 as the amount of fertilizer in T2, I had their variations as the following:
x1' = (2 l/min)*(x2/100) - (2 l/min)*(x1/100)
x2' = (2 l/min)*(x1/100) - (2 l/min)*(x2/100)
And then I couldn't go any further, since it doesn't make any sense. It is the same as saying x1'= - x2'
This is brilliant Mr. Khan. I think that Daniel does not need my help.Assume that:
the concentration of fertilizer at a time (t) for tank (1) = c1(t) kg/L
the concentration of fertilizer at a time (t) for tank (2) = c2(t) kg/L
Initial conditions
c1(0) = 0 and
c2(0) = 150/100 = 1.5 kg/L
During any time span δt (min) the volume of fluid exchanged = δV (liters) = 2 * δt
During the time span δt
Amount of fertilizer transported into the tank (1) = c2 * δV
Amount of fertilizer transported out of the tank (1) = c1 * δV
Amount of fertilizer transported into the tank (2) = c1 * δV
Amount of fertilizer transported out of the tank (2) = c2 * δV
Continue.....