harpazo
Full Member
- Joined
- Jan 31, 2013
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- 891
The sum of the digits of a 2-digit number is 13. If 18 is added to the number, the result is the number with its digits reversed. Find the original number.
Solution:
Let a = tens digit
Let b = ones digit
a + b = 13
18+ 10a + b = 10b + a
Is this the correct set up?
Solution:
Let a = tens digit
Let b = ones digit
a + b = 13
18+ 10a + b = 10b + a
Is this the correct set up?