Dividing Polynomials

chris6379

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Aug 19, 2005
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I am working on dividing polynomials. Anyone have experiencein these. the question is (m^2+7/2m+3)/(2m+3). I need help as soon as possible.

Christina
 
chris6379 said:
I am working on dividing polynomials....the question is (m^2+7/2m+3)/(2m+3).
Is the expression:

. . . . .[m<sup>2</sup> + 7/(2m) + 3] / [2m + 3]

...or:

. . . . .[(m<sup>2</sup> + 7)/(2m + 3)] / [2m + 3]

...or:

. . . . .[m<sup>2</sup> + 7/(2m + 3)] / [2m + 3]

...or something else? And are you dividing polynomials, or simplifying complex fractions?

Thank you.

Eliz.
 
I am working on dividing polynomials. Anyone have experiencein these. the question is (m^2+7/2m+3)/(2m+3). I need help as soon as possible.

first thing you want to do is simplify it a little... sine you're dividing two fractions, just take the second fraction, switch it's numerator and denominator and divide:

m^2+7 1
--------- * ----
2m + 3 2m+3

then once you have your new fraction

m^2 + 7
-----------
4m^2 + 12m + 9

divide it out, making sure to imagine another 1 up there, for the 12m to be divided into...
 
chris6379 said:
I am working on dividing polynomials. Anyone have experiencein these. the question is (m^2+7/2m+3)/(2m+3). I need help as soon as possible. Christina

WHOA!

If you're working on dividing polynomial,
then WHO gave you (m^2+7/2m+3)/(2m+3) ?

You should be given something that makes SOME sense; like:
divide (2m^3 + 3m^2 + 14m + 21) by (2m + 3).
 
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