burgerandcheese
Junior Member
- Joined
- Jul 2, 2018
- Messages
- 85
Question: Find the factors of p(x) = 3x3 + 4x2 + 5x - 6
Here's what it says in the book I'm reading
I really don't understand the part where it says sx - t is not really a different factor from -sx + t. So you need consider only positive values of s. Can someone please explain it to me?
And as for the one below that, how did they conclude that 3 would be a common factor of the coefficients of p(x)? Is it because 3x ± 3 = 3(x ± 1) and 3x ± 6 = 3(x ± 2)?
Here's what it says in the book I'm reading
I really don't understand the part where it says sx - t is not really a different factor from -sx + t. So you need consider only positive values of s. Can someone please explain it to me?
And as for the one below that, how did they conclude that 3 would be a common factor of the coefficients of p(x)? Is it because 3x ± 3 = 3(x ± 1) and 3x ± 6 = 3(x ± 2)?