Domain of the Function g(x) = 4 - x / x + 8; find g(h + 2)

chesterdg123

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Jun 9, 2008
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21
g(x)= 4-x/x+8

The denominator cannot equal zero, therefore the domain of the function is not equal to -8.

(-?, -8) and (-8, ?)

Also find g(h+2)

=4-h+2/h+2+8

=4-h+2 (8)
-------------
h+2+8(4)

=-h+2/h+2

=-1

Does this look right??? Thanks!
 
Re: Domain of the Function

chesterdg123 said:
g(x)= 4-x/x+8

The denominator cannot equal zero, therefore the domain of the function is not equal to -8.


(-?, -8) and (-8, ?)..........correct


Also find g(h+2)

=[4-(h+2)]/[h+2+8]

\(\displaystyle g(h+2)\, = \, \frac{2\, - \, h}{h\, + \, 10}\)
_____________________________________________
=4-h+2 (8) <--- How are you getting these multiplication by 8 or whatever you are trying to do
-------------
h+2+8(4)

=-h+2/h+2

=-1

Does this look right??? Thanks!
 
Re: Domain of the Function

=4-(h+2)
-------------
(h+2)+8

=4-h-2
---------
h+2+8

=2-h
-------
h+10

=1-h
-------
h+5
 
You simply must figure out at least two things in order to communicate effectively.

1) Order of operations.
2) HTML ignores spacing.

4 - x/x + 8 = 4 - 1 + 8 = 3 + 8 = 11

I suspect this is not what you want. Use parentheses and group as intended.

(4 - x)/(x + 8) -- This is a whole different animal.

=stuff
---------
otherstuff

This just doesn't work. Either use parentheses to clarify intent or learn just a little LaTeX. (See "Forum Help" at the top of the screen.)

As for your algebra,...

\(\displaystyle \frac{2-h}{h+10}\)

Name for me, please, the FACTORS in the numerator and in the denominator. Only FACTORS. What are they?
 
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