Don't know how to solve

Nexus

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Dec 18, 2005
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Yeah...I don't really understand this problem. Can someone please help me?

An observer 2 miles from the launching pad observes a vertically ascending missile at an angle of elevation of 21º. Five seconds later, the angle has increased to 35º. How Far did the missile travel during the 5-second interval? What was its average speed during this interval? If it keeps going vertically at the same average speed, what will its angle of elevation be 15 seconds after the first sighting?
 
Tan(21) = H<sub>1</sub>/2
H<sub>1</sub>=2tan(21)
Tan(35) = H<sub>2</sub>/2
H<sub>2</sub>=2tan(35)
H<sub>2</sub> - H<sub>1</sub>/2 =
2(tan(35)-tan(21)) miles per 5 seconds.
15 seconds after the first sighting it will be
10 * the average velocity higher than H<sub>2</sub> or
15 * the average velocity higher than H<sub>1</sub>
 
Thanks dude. I was asking one of my friends and finally realized I was reading the problem really wrong, thats why it didn't make sense. Now I know my answers are right.
 
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