Hey guys,
I'm having trouble with this problem set I'm working on at the moment. I'd appreciate some help with this question:
Therefore, using the theorem, I computed f'(0) = -2 + C, where C=2 (computed via substitution).
Also, I took the integral of f'(t) to compute the final answer, which is:
f(t) = 2e^(-t) - (cosπt/ π^2) + 2t + 1/(π^2) - 2.
Am I on the right track?
Thanks in advance, guys.
Thanks in advance.
I'm having trouble with this problem set I'm working on at the moment. I'd appreciate some help with this question:
Alright, so I simply integrated f''(x) up to f(t) given f(0) = 0 and f(1) = 0. This necessitates the mean value theorem to find f'(c), which is a coordinate for f'(t).Find f(t) if f"(t) = 2e^(-t) + cos(pi*t), f(0) = f(1) = 0. Give exact answers.
Therefore, using the theorem, I computed f'(0) = -2 + C, where C=2 (computed via substitution).
Also, I took the integral of f'(t) to compute the final answer, which is:
f(t) = 2e^(-t) - (cosπt/ π^2) + 2t + 1/(π^2) - 2.
Am I on the right track?
Thanks in advance, guys.
Thanks in advance.
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