P Puk3s New member Joined Oct 20, 2010 Messages 3 Oct 21, 2010 #1 dy/dx=ycosx/(1+y^2) This didnt look very hard to me but I ended up with lny + y^2/2 = sinx and I dont know how to solve that for Y
dy/dx=ycosx/(1+y^2) This didnt look very hard to me but I ended up with lny + y^2/2 = sinx and I dont know how to solve that for Y
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Oct 21, 2010 #2 \(\displaystyle You \ can't \ (solve \ for \ y), \ leave \ it \ as \ is.\)