Dy/dx

If ln(x+y)=tan^-1(y) then find dy/dx
You've posted this to "Differential Equations", which means that you've completed calculus. Where are you stuck on this implicit differentiation?

Please be complete. Thank you! ;)
 
If ln(x+y)=tan^-1(y) then find dy/dx


Any clues?
This is not a differential equation, it is just asking you to find the derivative of a function. Have you not taken Calculus? You should have learned that the derivative of ln(x) is 1/x and the derivative of tan^-1(x) is 1/(1+ x^2). Those and the chain rule are all you need.
 
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