e^x+e^y=e^xe^y, dy/dx=-e^(y-x)?

xeonph

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Sep 14, 2014
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how to get this answer please dy/dx=-e^(y-x) from e^x+e^y=e^xe^y ? please include the solution and the simplification process, tnx
 
how to get this answer please dy/dx=-e^(y-x) from e^x+e^y=e^xe^y ? please include the solution and the simplification process, tnx
While there are sites that provide hand-in solutions to homework, this isn't one of those. Sorry. :shock:

What did you get when you differentiated implicitly with respect to x? Please reply showing all of your steps. Thank you! ;)
 
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