moosie2323
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- Sep 26, 2008
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How would I set this problem up to solve by the elimination method
4x^2-9y^2+132=0
x^2+4y^2-67=0
4x^2-9y^2+132=0
x^2+4y^2-67=0
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elimination method
- Thread starter moosie2323
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moosie2323 said:How would I set this problem up to solve by the elimination method
4x^2-9y^2+132=0
x^2+4y^2-67=0
\(\displaystyle 4x^2 - 9y^2 = -132\)
\(\displaystyle x^2 + 4y^2 = 67\)
mMm, Let us eliminate x . So I'll multiply the second equation with ( -4 ).
\(\displaystyle 4x^2 - 9y^2 = -132\)
\(\displaystyle -4x^2 - 16y^2 = -268\)
.
.
\(\displaystyle -25y^2 = -400\)
\(\displaystyle y^2 =\frac{400}{25}\)
\(\displaystyle y^2 = 16\)
\(\displaystyle y = -+ 4\)
Now substitute y^2= 16 in the second equation to find x, knowing that x also have two values.
D
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Aladdin said:\(\displaystyle y = -+ 4\)
Now substitute y^2= 16 in the second equation to find x, knowing that x also have two values.
in LaTex you can use "\pm" to get ±.
like
\(\displaystyle \pm 4\)
Subhotosh Khan said:Aladdin said:\(\displaystyle y = -+ 4\)
Now substitute y^2= 16 in the second equation to find x, knowing that x also have two values.
in LaTex you can use "\pm" to get ±.
like
\(\displaystyle \pm 4\)
Thank you Mr khan.