Ellipse based question

[Nainish]

How do I find the intersection of an ellipse with coordinate axes? actually my equation is (x+3)^2/9 + (y-1)^2/4 = 1. Now in this whne I put up x=0 then y comes to be 3 but when I put up y=0 then I am getting two values of x both in negative. So which one to prefer. One is - 5.4…. And other is - 0.4…

 

[Deleted member 4993]

How do I find the intersection of an ellipse with coordinate axes? actually my equation is (x+3)^2/9 + (y-1)^2/4 = 1. Now in this whne I put up x=0 then y comes to be 3 but when I put up y=0 then I am getting two values of x both in negative. So which one to prefer. One is - 5.4…. And other is - 0.4…

Please show your work for putting x = 0.

Also, show your work for putting y = 0.

 

[pka]

Look at THIS PLOT

 

[Nainish]

In question I have done a mistake, my y is 1 and x have two values. See my solution please and tell which value of x shoudl I consider.

 

[Deleted member 4993]

How do I find the intersection of an ellipse with coordinate axes? actually my equation is (x+3)^2/9 + (y-1)^2/4 = 1. Now in this whne I put up x=0 then y comes to be 3 but when I put up y=0 then I am getting two values of x both in negative. So which one to prefer. One is - 5.4…. And other is - 0.4…

The stated ellipse is tangential to the y axis at (0,1) and it intersects x-axis at two points. Both of those points are valid points. Depending on the question,
one or the other or both will be used.